16-49b^2=0

Solution for 16-49b^2=0 equation:

16-49b^2=0

a = -49; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-49)·16
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*-49}=\frac{-56}{-98}
=4/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*-49}=\frac{56}{-98}
=-4/7
$